Create entities by using MS Sql in asp.net

July 25, 2013

Hello,

Sometime it is very difficult stuff to create entities for each table.

Here is a stored procedure,where we have to pass just table name only and it will automatically create entities(output as a string message)  as an output.

I’ve table Database named MyTest,which is containing table dbo.tblSLtest which structure is like a

structure

For create the entities for this table execute this stored procedure

DECLARE @TableName VARCHAR(MAX) = ‘tblSLtest’
DECLARE @TableSchema VARCHAR(MAX) = ‘dbo’
DECLARE @result varchar(max) = ”

SET @result = @result + ‘using System;’ + CHAR(13) + CHAR(13)

IF (@TableSchema IS NOT NULL)
BEGIN
SET @result = @result + ‘namespace ‘ + @TableSchema  + CHAR(13) + ‘{‘ + CHAR(13)
END

SET @result = @result + ‘public class ‘ + @TableName + CHAR(13) + ‘{‘ + CHAR(13)

SET @result = @result + ‘#region Instance Properties’ + CHAR(13)

SELECT @result = @result + CHAR(13)
+ ‘ public ‘ + ColumnType + ‘ ‘ + ColumnName + ‘ { get; set; } ‘ + CHAR(13)
FROM
(
SELECT  c.COLUMN_NAME   AS ColumnName
, CASE c.DATA_TYPE
WHEN ‘bigint’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Int64?’ ELSE ‘Int64’ END
WHEN ‘binary’ THEN ‘Byte[]’
WHEN ‘bit’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Boolean?’ ELSE ‘Boolean’ END
WHEN ‘char’ THEN ‘String’
WHEN ‘date’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTime?’ ELSE ‘DateTime’ END
WHEN ‘datetime’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTime?’ ELSE ‘DateTime’ END
WHEN ‘datetime2’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTime?’ ELSE ‘DateTime’ END
WHEN ‘datetimeoffset’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTimeOffset?’ ELSE ‘DateTimeOffset’ END
WHEN ‘decimal’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Decimal?’ ELSE ‘Decimal’ END
WHEN ‘float’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Single?’ ELSE ‘Single’ END
WHEN ‘image’ THEN ‘Byte[]’
WHEN ‘int’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Int32?’ ELSE ‘Int32’ END
WHEN ‘money’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Decimal?’ ELSE ‘Decimal’ END
WHEN ‘nchar’ THEN ‘String’
WHEN ‘ntext’ THEN ‘String’
WHEN ‘numeric’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Decimal?’ ELSE ‘Decimal’ END
WHEN ‘nvarchar’ THEN ‘String’
WHEN ‘real’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Double?’ ELSE ‘Double’ END
WHEN ‘smalldatetime’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTime?’ ELSE ‘DateTime’ END
WHEN ‘smallint’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Int16?’ ELSE ‘Int16’END
WHEN ‘smallmoney’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Decimal?’ ELSE ‘Decimal’ END
WHEN ‘text’ THEN ‘String’
WHEN ‘time’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘TimeSpan?’ ELSE ‘TimeSpan’ END
WHEN ‘timestamp’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘DateTime?’ ELSE ‘DateTime’ END
WHEN ‘tinyint’ THEN
CASE C.IS_NULLABLE
WHEN ‘YES’ THEN ‘Byte?’ ELSE ‘Byte’ END
WHEN ‘uniqueidentifier’ THEN ‘Guid’
WHEN ‘varbinary’ THEN ‘Byte[]’
WHEN ‘varchar’ THEN ‘String’
ELSE ‘Object’
END AS ColumnType
, c.ORDINAL_POSITION
FROM    INFORMATION_SCHEMA.COLUMNS c
WHERE   c.TABLE_NAME = @TableName and ISNULL(@TableSchema, c.TABLE_SCHEMA) = c.TABLE_SCHEMA
) t
ORDER BY t.ORDINAL_POSITION

SET @result = @result + CHAR(13) + ‘#endregion Instance Properties’ + CHAR(13)

SET @result = @result  + ‘}’ + CHAR(13)

IF (@TableSchema IS NOT NULL)
BEGIN
SET @result = @result + CHAR(13) + ‘}’
END

PRINT @result

and you we have output like(with corresponding datatypes)

output

So now enjoy with entities…


Get day count for particular month using MS Sql

July 24, 2013

Hello,

By using below code you can find the day count-number of days in particular month

So here it is,

DECLARE @dtDate DATETIME
SET @dtDate = ‘8/18/2007’

select datediff(day, dateadd(day, 1-day(@dtDate), @dtDate),
dateadd(month, 1, dateadd(day, 1-day(@dtDate), @dtDate)))  as dayCount

you will get output like,

Capture

Here august month passed in dtDate parameter of sql so will have an output 31 day count.